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Some elementary explicit bounds for two mollifications of the Moebius function O. Ramare March 8, 2012 Abstract We prove that the sum ∑ { d≤x, (d,r)=1 µ(d)/d1+? is bounded by 1 + ?, uniformly in x ≥ 1, r and ? > 0. We prove a similar estimate for the quantity ∑ { d≤x, (d,r)=1 µ(d) Log(x/d)/d1+?. When ? = 0, r varies between 1 and a hundred, and x is below a million, this sum is non-negative and this raises the question as to whether it is non-negative for every x. 1 Introduction and results Our first result is the following: Theorem 1.1. When r ≥ 1 and ? ≥ 0, we have ? ? ? ? ∑ d≤x, (d,r)=1 µ(d) d1+? ? ? ? ? ≤ 1 + ?. This Lemma generalizes the estimate of [5, Lemme 10.2] which corre- sponds to the case ? = 0. This generalization is not straightforward at all and requires a change of proof. The case ? = 0 and r = 1 is classical.
- follows readily
- ??1 ?
- explicit estimates
- also ≤
- very erratical
- when ?
- moebius function
- useful when applying
- lowest lower bound
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English