22-1 1. I

• cours magistral - matière potentielle : practical cells
• cours magistral
• cours magistral - matière potentielle : problems

22-1 Homework solutions 1. I2 + 2e 2I- Na+ + e Na } the half cell with the more -ve E will be the anode E(I2) > E (Na) 2. Au + + e Au I2 + 2e 2I- The way to do these is to write out both as reductions and then from info given see which is the anode --it will have the most negative E } anode E(Au) > E (I) 3.

• -3 lecture
• cathode cell compartment
• standard cell
• solution by reduction to cu
• ni2
• -4 equation review
• reaction
• cell